36x^4-y^2-2/3y-1/9

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Solution for 36x^4-y^2-2/3y-1/9 equation: 


x in (-oo:+oo)

36*x^4-y^2-((2/3)*y)-(1/9) = 0

36*x^4-y^2+(-2/3)*y-1/9 = 0

36*x^4 = -(-y^2-2/3*y-1/9) // : 36

x^4 = (y^2-(-2/3*y)+1/9)/36

x^4 = (y^2+2/3*y+1/9)/36 // ^ 1/4

abs(x) = ((y^2+2/3*y+1/9)^(1/4))/(36^(1/4))

x = ((y^2+2/3*y+1/9)^(1/4))/(36^(1/4)) or x = -(((y^2+2/3*y+1/9)^(1/4))/(36^(1/4)))

x in { ((y^2+2/3*y+1/9)^(1/4))/(36^(1/4)), -(((y^2+2/3*y+1/9)^(1/4))/(36^(1/4))) }

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